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-4u(u+5)-3(u+5)=0
We multiply parentheses
-4u^2-20u-3u-15=0
We add all the numbers together, and all the variables
-4u^2-23u-15=0
a = -4; b = -23; c = -15;
Δ = b2-4ac
Δ = -232-4·(-4)·(-15)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-17}{2*-4}=\frac{6}{-8} =-3/4 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+17}{2*-4}=\frac{40}{-8} =-5 $
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