-4v+2=-2(2v-1)+6v

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Solution for -4v+2=-2(2v-1)+6v equation: 



-4v+2=-2(2v-1)+6v

We move all terms to the left:

-4v+2-(-2(2v-1)+6v)=0



We calculate terms in parentheses: -(-2(2v-1)+6v), so:

-2(2v-1)+6v

We add all the numbers together, and all the variables

6v-2(2v-1)

We multiply parentheses

6v-4v+2

We add all the numbers together, and all the variables

2v+2

Back to the equation:

-(2v+2)



We get rid of parentheses

-4v-2v-2+2=0

We add all the numbers together, and all the variables

-6v=0

v=0/-6

v=0

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