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-4v+2=-2(2v-1)+6v
We move all terms to the left:
-4v+2-(-2(2v-1)+6v)=0
We calculate terms in parentheses: -(-2(2v-1)+6v), so:We get rid of parentheses
-2(2v-1)+6v
We add all the numbers together, and all the variables
6v-2(2v-1)
We multiply parentheses
6v-4v+2
We add all the numbers together, and all the variables
2v+2
Back to the equation:
-(2v+2)
-4v-2v-2+2=0
We add all the numbers together, and all the variables
-6v=0
v=0/-6
v=0
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