-4v-22=6(v-2)

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Solution for -4v-22=6(v-2) equation: 



-4v-22=6(v-2)

We move all terms to the left:

-4v-22-(6(v-2))=0



We calculate terms in parentheses: -(6(v-2)), so:

6(v-2)

We multiply parentheses

6v-12

Back to the equation:

-(6v-12)



We get rid of parentheses

-4v-6v+12-22=0

We add all the numbers together, and all the variables

-10v-10=0

We move all terms containing v to the left, all other terms to the right

-10v=10

v=10/-10

v=-1

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