-4v-2=2v-2+((v+100)/4)

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Solution for -4v-2=2v-2+((v+100)/4) equation: 



-4v-2=2v-2+((v+100)/4)

We move all terms to the left:

-4v-2-(2v-2+((v+100)/4))=0

We multiply all the terms by the denominator


-4v*4))-(2v-2+((v+100)-2*4))=0

We add all the numbers together, and all the variables

-4v*4))-(2v-2+((v+100)=0

Wy multiply elements

-16v^2=0

a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{0}{-32}=0$

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