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-4x(2x+4)+3x+2=-44
We move all terms to the left:
-4x(2x+4)+3x+2-(-44)=0
We add all the numbers together, and all the variables
3x-4x(2x+4)+46=0
We multiply parentheses
-8x^2+3x-16x+46=0
We add all the numbers together, and all the variables
-8x^2-13x+46=0
a = -8; b = -13; c = +46;
Δ = b2-4ac
Δ = -132-4·(-8)·46
Δ = 1641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{1641}}{2*-8}=\frac{13-\sqrt{1641}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{1641}}{2*-8}=\frac{13+\sqrt{1641}}{-16} $
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