-4x(2x-7)=3(52-4x)

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Solution for -4x(2x-7)=3(52-4x) equation: 



-4x(2x-7)=3(52-4x)

We move all terms to the left:

-4x(2x-7)-(3(52-4x))=0

We add all the numbers together, and all the variables

-4x(2x-7)-(3(-4x+52))=0

We multiply parentheses

-8x^2+28x-(3(-4x+52))=0



We calculate terms in parentheses: -(3(-4x+52)), so:

3(-4x+52)

We multiply parentheses

-12x+156

Back to the equation:

-(-12x+156)



We get rid of parentheses

-8x^2+28x+12x-156=0

We add all the numbers together, and all the variables

-8x^2+40x-156=0

a = -8; b = 40; c = -156;
Δ = b2-4ac
Δ = 402-4·(-8)·(-156)
Δ = -3392
Delta is less than zero, so there is no solution for the equation

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