-4x(3-2x)=5

Solution for -4x(3-2x)=5 equation:

-4x(3-2x)=5

We move all terms to the left:

-4x(3-2x)-(5)=0

We add all the numbers together, and all the variables

-4x(-2x+3)-5=0

We multiply parentheses

8x^2-12x-5=0

a = 8; b = -12; c = -5;
Δ = b2-4ac
Δ = -122-4·8·(-5)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{19}}{2*8}=\frac{12-4\sqrt{19}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{19}}{2*8}=\frac{12+4\sqrt{19}}{16}
$