-4x(4x-5)=4x

Solution for -4x(4x-5)=4x equation:

-4x(4x-5)=4x

We move all terms to the left:

-4x(4x-5)-(4x)=0

We add all the numbers together, and all the variables

-4x-4x(4x-5)=0

We multiply parentheses

-16x^2-4x+20x=0

We add all the numbers together, and all the variables

-16x^2+16x=0

a = -16; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-16)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-16}=\frac{-32}{-32}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-16}=\frac{0}{-32}
=0
$