-4x(4x-9)-x=-4(x-3)

Solution for -4x(4x-9)-x=-4(x-3) equation:

-4x(4x-9)-x=-4(x-3)

We move all terms to the left:

-4x(4x-9)-x-(-4(x-3))=0

We add all the numbers together, and all the variables

-1x-4x(4x-9)-(-4(x-3))=0

We multiply parentheses

-16x^2-1x+36x-(-4(x-3))=0


We calculate terms in parentheses: -(-4(x-3)), so:

-4(x-3)

We multiply parentheses

-4x+12

Back to the equation:

-(-4x+12)


We add all the numbers together, and all the variables

-16x^2+35x-(-4x+12)=0

We get rid of parentheses

-16x^2+35x+4x-12=0

We add all the numbers together, and all the variables

-16x^2+39x-12=0

a = -16; b = 39; c = -12;
Δ = b2-4ac
Δ = 392-4·(-16)·(-12)
Δ = 753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-\sqrt{753}}{2*-16}=\frac{-39-\sqrt{753}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+\sqrt{753}}{2*-16}=\frac{-39+\sqrt{753}}{-32}
$