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-4x(5x-8)=-48
We move all terms to the left:
-4x(5x-8)-(-48)=0
We add all the numbers together, and all the variables
-4x(5x-8)+48=0
We multiply parentheses
-20x^2+32x+48=0
a = -20; b = 32; c = +48;
Δ = b2-4ac
Δ = 322-4·(-20)·48
Δ = 4864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4864}=\sqrt{256*19}=\sqrt{256}*\sqrt{19}=16\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16\sqrt{19}}{2*-20}=\frac{-32-16\sqrt{19}}{-40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16\sqrt{19}}{2*-20}=\frac{-32+16\sqrt{19}}{-40} $
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