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-4x(7x+5)=-160
We move all terms to the left:
-4x(7x+5)-(-160)=0
We add all the numbers together, and all the variables
-4x(7x+5)+160=0
We multiply parentheses
-28x^2-20x+160=0
a = -28; b = -20; c = +160;
Δ = b2-4ac
Δ = -202-4·(-28)·160
Δ = 18320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18320}=\sqrt{16*1145}=\sqrt{16}*\sqrt{1145}=4\sqrt{1145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{1145}}{2*-28}=\frac{20-4\sqrt{1145}}{-56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{1145}}{2*-28}=\frac{20+4\sqrt{1145}}{-56} $
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