-4x(8-3x)-(112)=0

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Solution for -4x(8-3x)-(112)=0 equation:



-4x(8-3x)-(112)=0
We add all the numbers together, and all the variables
-4x(-3x+8)-112=0
We multiply parentheses
12x^2-32x-112=0
a = 12; b = -32; c = -112;
Δ = b2-4ac
Δ = -322-4·12·(-112)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-80}{2*12}=\frac{-48}{24} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+80}{2*12}=\frac{112}{24} =4+2/3 $

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