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-4x(x+2)=6x+12
We move all terms to the left:
-4x(x+2)-(6x+12)=0
We multiply parentheses
-4x^2-8x-(6x+12)=0
We get rid of parentheses
-4x^2-8x-6x-12=0
We add all the numbers together, and all the variables
-4x^2-14x-12=0
a = -4; b = -14; c = -12;
Δ = b2-4ac
Δ = -142-4·(-4)·(-12)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*-4}=\frac{12}{-8} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*-4}=\frac{16}{-8} =-2 $
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