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-4x(x-2)=2x-4
We move all terms to the left:
-4x(x-2)-(2x-4)=0
We multiply parentheses
-4x^2+8x-(2x-4)=0
We get rid of parentheses
-4x^2+8x-2x+4=0
We add all the numbers together, and all the variables
-4x^2+6x+4=0
a = -4; b = 6; c = +4;
Δ = b2-4ac
Δ = 62-4·(-4)·4
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-10}{2*-4}=\frac{-16}{-8} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+10}{2*-4}=\frac{4}{-8} =-1/2 $
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