-4x(x-3)+2x=10

Solution for -4x(x-3)+2x=10 equation:

-4x(x-3)+2x=10

We move all terms to the left:

-4x(x-3)+2x-(10)=0

We add all the numbers together, and all the variables

2x-4x(x-3)-10=0

We multiply parentheses

-4x^2+2x+12x-10=0

We add all the numbers together, and all the variables

-4x^2+14x-10=0

a = -4; b = 14; c = -10;
Δ = b2-4ac
Δ = 142-4·(-4)·(-10)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6}{2*-4}=\frac{-20}{-8}
=2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6}{2*-4}=\frac{-8}{-8}
=1
$