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-4x+10=x2+13x-6
We move all terms to the left:
-4x+10-(x2+13x-6)=0
We add all the numbers together, and all the variables
-(+x^2+13x-6)-4x+10=0
We get rid of parentheses
-x^2-13x-4x+6+10=0
We add all the numbers together, and all the variables
-1x^2-17x+16=0
a = -1; b = -17; c = +16;
Δ = b2-4ac
Δ = -172-4·(-1)·16
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{353}}{2*-1}=\frac{17-\sqrt{353}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{353}}{2*-1}=\frac{17+\sqrt{353}}{-2} $
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