-4x+2(6x-4)=40

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Solution for -4x+2(6x-4)=40 equation: 



-4x+2(6x-4)=40

We move all terms to the left:

-4x+2(6x-4)-(40)=0

We multiply parentheses

-4x+12x-8-40=0

We add all the numbers together, and all the variables

8x-48=0

We move all terms containing x to the left, all other terms to the right

8x=48

x=48/8

x=6

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