-4x+3(1-4x)=8(1-4x)-5

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Solution for -4x+3(1-4x)=8(1-4x)-5 equation:



-4x+3(1-4x)=8(1-4x)-5
We move all terms to the left:
-4x+3(1-4x)-(8(1-4x)-5)=0
We add all the numbers together, and all the variables
-4x+3(-4x+1)-(8(-4x+1)-5)=0
We multiply parentheses
-4x-12x-(8(-4x+1)-5)+3=0
We calculate terms in parentheses: -(8(-4x+1)-5), so:
8(-4x+1)-5
We multiply parentheses
-32x+8-5
We add all the numbers together, and all the variables
-32x+3
Back to the equation:
-(-32x+3)
We add all the numbers together, and all the variables
-16x-(-32x+3)+3=0
We get rid of parentheses
-16x+32x-3+3=0
We add all the numbers together, and all the variables
16x=0
x=0/16
x=0

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