-4x+4(7+8x)=2(14x-5)+38

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Solution for -4x+4(7+8x)=2(14x-5)+38 equation:



-4x+4(7+8x)=2(14x-5)+38
We move all terms to the left:
-4x+4(7+8x)-(2(14x-5)+38)=0
We add all the numbers together, and all the variables
-4x+4(8x+7)-(2(14x-5)+38)=0
We multiply parentheses
-4x+32x-(2(14x-5)+38)+28=0
We calculate terms in parentheses: -(2(14x-5)+38), so:
2(14x-5)+38
We multiply parentheses
28x-10+38
We add all the numbers together, and all the variables
28x+28
Back to the equation:
-(28x+28)
We add all the numbers together, and all the variables
28x-(28x+28)+28=0
We get rid of parentheses
28x-28x-28+28=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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