-4x+8x=(x-3)-5

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Solution for -4x+8x=(x-3)-5 equation: 



-4x+8x=(x-3)-5

We move all terms to the left:

-4x+8x-((x-3)-5)=0

We add all the numbers together, and all the variables

4x-((x-3)-5)=0



We calculate terms in parentheses: -((x-3)-5), so:

(x-3)-5

We get rid of parentheses

x-3-5

We add all the numbers together, and all the variables

x-8

Back to the equation:

-(x-8)



We get rid of parentheses

4x-x+8=0

We add all the numbers together, and all the variables

3x+8=0

We move all terms containing x to the left, all other terms to the right

3x=-8

x=-8/3

x=-2+2/3

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