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-4x+x=-6+1/5x
We move all terms to the left:
-4x+x-(-6+1/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-4x+x-(1/5x-6)=0
We add all the numbers together, and all the variables
-3x-(1/5x-6)=0
We get rid of parentheses
-3x-1/5x+6=0
We multiply all the terms by the denominator
-3x*5x+6*5x-1=0
Wy multiply elements
-15x^2+30x-1=0
a = -15; b = 30; c = -1;
Δ = b2-4ac
Δ = 302-4·(-15)·(-1)
Δ = 840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{840}=\sqrt{4*210}=\sqrt{4}*\sqrt{210}=2\sqrt{210}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{210}}{2*-15}=\frac{-30-2\sqrt{210}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{210}}{2*-15}=\frac{-30+2\sqrt{210}}{-30} $
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