-4x-5x(x-13)=2

Solution for -4x-5x(x-13)=2 equation:

-4x-5x(x-13)=2

We move all terms to the left:

-4x-5x(x-13)-(2)=0

We multiply parentheses

-5x^2-4x+65x-2=0

We add all the numbers together, and all the variables

-5x^2+61x-2=0

a = -5; b = 61; c = -2;
Δ = b2-4ac
Δ = 612-4·(-5)·(-2)
Δ = 3681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3681}=\sqrt{9*409}=\sqrt{9}*\sqrt{409}=3\sqrt{409}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-3\sqrt{409}}{2*-5}=\frac{-61-3\sqrt{409}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+3\sqrt{409}}{2*-5}=\frac{-61+3\sqrt{409}}{-10}
$