-4x-8=4(-3x2)

Solution for -4x-8=4(-3x2) equation:

-4x-8=4(-3x^2)

We move all terms to the left:

-4x-8-(4(-3x^2))=0


We calculate terms in parentheses: -(4(-3x^2)), so:

4(-3x^2)

We multiply parentheses

-12x^2

Back to the equation:

-(-12x^2)


We get rid of parentheses

12x^2-4x-8=0

a = 12; b = -4; c = -8;
Δ = b2-4ac
Δ = -42-4·12·(-8)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-20}{2*12}=\frac{-16}{24}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+20}{2*12}=\frac{24}{24}
=1
$