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-4x/5+4/5=5x/2+x
We move all terms to the left:
-4x/5+4/5-(5x/2+x)=0
Domain of the equation: 2+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-2
x!=-2/1
x!=-2
x∈R
-4x/5-(+x+5x/2)+4/5=0
We get rid of parentheses
-4x/5-x-5x/2+4/5=0
We calculate fractions
There is no solution for this equation
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