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-4x^2+12x+15=-25
We move all terms to the left:
-4x^2+12x+15-(-25)=0
We add all the numbers together, and all the variables
-4x^2+12x+40=0
a = -4; b = 12; c = +40;
Δ = b2-4ac
Δ = 122-4·(-4)·40
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-28}{2*-4}=\frac{-40}{-8} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+28}{2*-4}=\frac{16}{-8} =-2 $
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