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-4x^2+16x+9=0
a = -4; b = 16; c = +9;
Δ = b2-4ac
Δ = 162-4·(-4)·9
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-20}{2*-4}=\frac{-36}{-8} =4+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+20}{2*-4}=\frac{4}{-8} =-1/2 $
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