-4x2+16x-16=0

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Solution for -4x2+16x-16=0 equation: 



-4x^2+16x-16=0

a = -4; b = 16; c = -16;
Δ = b2-4ac
Δ = 162-4·(-4)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{-8}=+2$

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