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-4x^2+60x-125=0
a = -4; b = 60; c = -125;
Δ = b2-4ac
Δ = 602-4·(-4)·(-125)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-40}{2*-4}=\frac{-100}{-8} =12+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+40}{2*-4}=\frac{-20}{-8} =2+1/2 $
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