-4x2+x=-4

Solution for -4x2+x=-4 equation:

-4x^2+x=-4

We move all terms to the left:

-4x^2+x-(-4)=0

We add all the numbers together, and all the variables

-4x^2+x+4=0

a = -4; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·(-4)·4
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{65}}{2*-4}=\frac{-1-\sqrt{65}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{65}}{2*-4}=\frac{-1+\sqrt{65}}{-8}
$