-4x2-12x+9=0

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Solution for -4x2-12x+9=0 equation:



-4x^2-12x+9=0
a = -4; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·(-4)·9
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{2}}{2*-4}=\frac{12-12\sqrt{2}}{-8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{2}}{2*-4}=\frac{12+12\sqrt{2}}{-8} $

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