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-4x^2-15x=4=0
We move all terms to the left:
-4x^2-15x-(4)=0
a = -4; b = -15; c = -4;
Δ = b2-4ac
Δ = -152-4·(-4)·(-4)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{161}}{2*-4}=\frac{15-\sqrt{161}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{161}}{2*-4}=\frac{15+\sqrt{161}}{-8} $
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