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-4x^2-26x-22=0
a = -4; b = -26; c = -22;
Δ = b2-4ac
Δ = -262-4·(-4)·(-22)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-18}{2*-4}=\frac{8}{-8} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+18}{2*-4}=\frac{44}{-8} =-5+1/2 $
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