-4x2-5x+9=0

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Solution for -4x2-5x+9=0 equation:



-4x^2-5x+9=0
a = -4; b = -5; c = +9;
Δ = b2-4ac
Δ = -52-4·(-4)·9
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-13}{2*-4}=\frac{-8}{-8} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+13}{2*-4}=\frac{18}{-8} =-2+1/4 $

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