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-4x^2-84x-440=0
a = -4; b = -84; c = -440;
Δ = b2-4ac
Δ = -842-4·(-4)·(-440)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-4}{2*-4}=\frac{80}{-8} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+4}{2*-4}=\frac{88}{-8} =-11 $
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