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-4x^2/3=-2
We move all terms to the left:
-4x^2/3-(-2)=0
We add all the numbers together, and all the variables
-4x^2/3+2=0
We multiply all the terms by the denominator
-4x^2+2*3=0
We add all the numbers together, and all the variables
-4x^2+6=0
a = -4; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·(-4)·6
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6}}{2*-4}=\frac{0-4\sqrt{6}}{-8} =-\frac{4\sqrt{6}}{-8} =-\frac{\sqrt{6}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6}}{2*-4}=\frac{0+4\sqrt{6}}{-8} =\frac{4\sqrt{6}}{-8} =\frac{\sqrt{6}}{-2} $
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