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-4x^2=24x+11
We move all terms to the left:
-4x^2-(24x+11)=0
We get rid of parentheses
-4x^2-24x-11=0
a = -4; b = -24; c = -11;
Δ = b2-4ac
Δ = -242-4·(-4)·(-11)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-20}{2*-4}=\frac{4}{-8} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+20}{2*-4}=\frac{44}{-8} =-5+1/2 $
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