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-4x=2/3x-14
We move all terms to the left:
-4x-(2/3x-14)=0
Domain of the equation: 3x-14)!=0We get rid of parentheses
x∈R
-4x-2/3x+14=0
We multiply all the terms by the denominator
-4x*3x+14*3x-2=0
Wy multiply elements
-12x^2+42x-2=0
a = -12; b = 42; c = -2;
Δ = b2-4ac
Δ = 422-4·(-12)·(-2)
Δ = 1668
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1668}=\sqrt{4*417}=\sqrt{4}*\sqrt{417}=2\sqrt{417}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-2\sqrt{417}}{2*-12}=\frac{-42-2\sqrt{417}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+2\sqrt{417}}{2*-12}=\frac{-42+2\sqrt{417}}{-24} $
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