-4x=3/4x-5

Solution for -4x=3/4x-5 equation:

-4x=3/4x-5

We move all terms to the left:

-4x-(3/4x-5)=0


Domain of the equation: 4x-5)!=0

x∈R


We get rid of parentheses

-4x-3/4x+5=0

We multiply all the terms by the denominator


-4x*4x+5*4x-3=0

Wy multiply elements

-16x^2+20x-3=0

a = -16; b = 20; c = -3;
Δ = b2-4ac
Δ = 202-4·(-16)·(-3)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{13}}{2*-16}=\frac{-20-4\sqrt{13}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{13}}{2*-16}=\frac{-20+4\sqrt{13}}{-32}
$