-4y(5y-5)-y=-3(y-3)

Solution for -4y(5y-5)-y=-3(y-3) equation:

-4y(5y-5)-y=-3(y-3)

We move all terms to the left:

-4y(5y-5)-y-(-3(y-3))=0

We add all the numbers together, and all the variables

-1y-4y(5y-5)-(-3(y-3))=0

We multiply parentheses

-20y^2-1y+20y-(-3(y-3))=0


We calculate terms in parentheses: -(-3(y-3)), so:

-3(y-3)

We multiply parentheses

-3y+9

Back to the equation:

-(-3y+9)


We add all the numbers together, and all the variables

-20y^2+19y-(-3y+9)=0

We get rid of parentheses

-20y^2+19y+3y-9=0

We add all the numbers together, and all the variables

-20y^2+22y-9=0

a = -20; b = 22; c = -9;
Δ = b2-4ac
Δ = 222-4·(-20)·(-9)
Δ = -236
Delta is less than zero, so there is no solution for the equation