-4y(y+3)=-4y+20

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Solution for -4y(y+3)=-4y+20 equation:



-4y(y+3)=-4y+20
We move all terms to the left:
-4y(y+3)-(-4y+20)=0
We multiply parentheses
-4y^2-12y-(-4y+20)=0
We get rid of parentheses
-4y^2-12y+4y-20=0
We add all the numbers together, and all the variables
-4y^2-8y-20=0
a = -4; b = -8; c = -20;
Δ = b2-4ac
Δ = -82-4·(-4)·(-20)
Δ = -256
Delta is less than zero, so there is no solution for the equation

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