-4y+30=-4/5y

Solution for -4y+30=-4/5y equation:

-4y+30=-4/5y

We move all terms to the left:

-4y+30-(-4/5y)=0


Domain of the equation: 5y)!=0

y!=0/1

y!=0

y∈R


We get rid of parentheses

-4y+4/5y+30=0

We multiply all the terms by the denominator


-4y*5y+30*5y+4=0

Wy multiply elements

-20y^2+150y+4=0

a = -20; b = 150; c = +4;
Δ = b2-4ac
Δ = 1502-4·(-20)·4
Δ = 22820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22820}=\sqrt{4*5705}=\sqrt{4}*\sqrt{5705}=2\sqrt{5705}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-2\sqrt{5705}}{2*-20}=\frac{-150-2\sqrt{5705}}{-40}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+2\sqrt{5705}}{2*-20}=\frac{-150+2\sqrt{5705}}{-40}
$