-4y+36=3(y-2)

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Solution for -4y+36=3(y-2) equation: 



-4y+36=3(y-2)

We move all terms to the left:

-4y+36-(3(y-2))=0



We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

-4y-3y+6+36=0

We add all the numbers together, and all the variables

-7y+42=0

We move all terms containing y to the left, all other terms to the right

-7y=-42

y=-42/-7

y=+6

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