-4y-(5y-3)=-7y+3-2y

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Solution for -4y-(5y-3)=-7y+3-2y equation:


Simplifying
-4y + -1(5y + -3) = -7y + 3 + -2y

Reorder the terms:
-4y + -1(-3 + 5y) = -7y + 3 + -2y
-4y + (-3 * -1 + 5y * -1) = -7y + 3 + -2y
-4y + (3 + -5y) = -7y + 3 + -2y

Reorder the terms:
3 + -4y + -5y = -7y + 3 + -2y

Combine like terms: -4y + -5y = -9y
3 + -9y = -7y + 3 + -2y

Reorder the terms:
3 + -9y = 3 + -7y + -2y

Combine like terms: -7y + -2y = -9y
3 + -9y = 3 + -9y

Add '-3' to each side of the equation.
3 + -3 + -9y = 3 + -3 + -9y

Combine like terms: 3 + -3 = 0
0 + -9y = 3 + -3 + -9y
-9y = 3 + -3 + -9y

Combine like terms: 3 + -3 = 0
-9y = 0 + -9y
-9y = -9y

Add '9y' to each side of the equation.
-9y + 9y = -9y + 9y

Combine like terms: -9y + 9y = 0
0 = -9y + 9y

Combine like terms: -9y + 9y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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