-4y=(3y+7)/2

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Solution for -4y=(3y+7)/2 equation: 



-4y=(3y+7)/2

We move all terms to the left:

-4y-((3y+7)/2)=0

We multiply all the terms by the denominator


-4y*2)-((3y+7)=0

Wy multiply elements

-8y^2=0

a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-16}=0$

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