-4z+2(3z+5)=-20

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Solution for -4z+2(3z+5)=-20 equation: 



-4z+2(3z+5)=-20

We move all terms to the left:

-4z+2(3z+5)-(-20)=0

We add all the numbers together, and all the variables

-4z+2(3z+5)+20=0

We multiply parentheses

-4z+6z+10+20=0

We add all the numbers together, and all the variables

2z+30=0

We move all terms containing z to the left, all other terms to the right

2z=-30

z=-30/2

z=-15

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