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-5((x)/(15)-16-30)=50-(1)/(3)x
We move all terms to the left:
-5((x)/(15)-16-30)-(50-(1)/(3)x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-5(x/15-46)-(-1/3x+50)=0
We multiply parentheses
-5x-(-1/3x+50)+230=0
We get rid of parentheses
-5x+1/3x-50+230=0
We multiply all the terms by the denominator
-5x*3x-50*3x+230*3x+1=0
Wy multiply elements
-15x^2-150x+690x+1=0
We add all the numbers together, and all the variables
-15x^2+540x+1=0
a = -15; b = 540; c = +1;
Δ = b2-4ac
Δ = 5402-4·(-15)·1
Δ = 291660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{291660}=\sqrt{4*72915}=\sqrt{4}*\sqrt{72915}=2\sqrt{72915}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(540)-2\sqrt{72915}}{2*-15}=\frac{-540-2\sqrt{72915}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(540)+2\sqrt{72915}}{2*-15}=\frac{-540+2\sqrt{72915}}{-30} $
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