-5(*x-3)+6=4-(x-2)

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Solution for -5(*x-3)+6=4-(x-2) equation: 



-5(*x-3)+6=4-(x-2)

We move all terms to the left:

-5(*x-3)+6-(4-(x-2))=0

We add all the numbers together, and all the variables

-5(x-3)-(4-(x-2))+6=0

We multiply parentheses

-5x-(4-(x-2))+15+6=0



We calculate terms in parentheses: -(4-(x-2)), so:

4-(x-2)

determiningTheFunctionDomain
-(x-2)+4

We get rid of parentheses

-x+2+4

We add all the numbers together, and all the variables

-1x+6

Back to the equation:

-(-1x+6)



We add all the numbers together, and all the variables

-5x-(-1x+6)+21=0

We get rid of parentheses

-5x+1x-6+21=0

We add all the numbers together, and all the variables

-4x+15=0

We move all terms containing x to the left, all other terms to the right

-4x=-15

x=-15/-4

x=3+3/4

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