-5(*x-3)+6=4-(x-2)

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Solution for -5(*x-3)+6=4-(x-2) equation:



-5(*x-3)+6=4-(x-2)
We move all terms to the left:
-5(*x-3)+6-(4-(x-2))=0
We add all the numbers together, and all the variables
-5(x-3)-(4-(x-2))+6=0
We multiply parentheses
-5x-(4-(x-2))+15+6=0
We calculate terms in parentheses: -(4-(x-2)), so:
4-(x-2)
determiningTheFunctionDomain -(x-2)+4
We get rid of parentheses
-x+2+4
We add all the numbers together, and all the variables
-1x+6
Back to the equation:
-(-1x+6)
We add all the numbers together, and all the variables
-5x-(-1x+6)+21=0
We get rid of parentheses
-5x+1x-6+21=0
We add all the numbers together, and all the variables
-4x+15=0
We move all terms containing x to the left, all other terms to the right
-4x=-15
x=-15/-4
x=3+3/4

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