-5(-2u+2)-2u=4(u-4)-4

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Solution for -5(-2u+2)-2u=4(u-4)-4 equation: 



-5(-2u+2)-2u=4(u-4)-4

We move all terms to the left:

-5(-2u+2)-2u-(4(u-4)-4)=0

We add all the numbers together, and all the variables

-2u-5(-2u+2)-(4(u-4)-4)=0

We multiply parentheses

-2u+10u-(4(u-4)-4)-10=0



We calculate terms in parentheses: -(4(u-4)-4), so:

4(u-4)-4

We multiply parentheses

4u-16-4

We add all the numbers together, and all the variables

4u-20

Back to the equation:

-(4u-20)



We add all the numbers together, and all the variables

8u-(4u-20)-10=0

We get rid of parentheses

8u-4u+20-10=0

We add all the numbers together, and all the variables

4u+10=0

We move all terms containing u to the left, all other terms to the right

4u=-10

u=-10/4

u=-2+1/2

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