-5(-2u+2)-2u=4(u-4)-4

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Solution for -5(-2u+2)-2u=4(u-4)-4 equation:



-5(-2u+2)-2u=4(u-4)-4
We move all terms to the left:
-5(-2u+2)-2u-(4(u-4)-4)=0
We add all the numbers together, and all the variables
-2u-5(-2u+2)-(4(u-4)-4)=0
We multiply parentheses
-2u+10u-(4(u-4)-4)-10=0
We calculate terms in parentheses: -(4(u-4)-4), so:
4(u-4)-4
We multiply parentheses
4u-16-4
We add all the numbers together, and all the variables
4u-20
Back to the equation:
-(4u-20)
We add all the numbers together, and all the variables
8u-(4u-20)-10=0
We get rid of parentheses
8u-4u+20-10=0
We add all the numbers together, and all the variables
4u+10=0
We move all terms containing u to the left, all other terms to the right
4u=-10
u=-10/4
u=-2+1/2

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