-5(-2z)+4(3-z)=7(3+z)

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Solution for -5(-2z)+4(3-z)=7(3+z) equation: 



-5(-2z)+4(3-z)=7(3+z)

We move all terms to the left:

-5(-2z)+4(3-z)-(7(3+z))=0

We add all the numbers together, and all the variables

-5(-2z)+4(-1z+3)-(7(z+3))=0

We multiply parentheses

10z-4z-(7(z+3))+12=0



We calculate terms in parentheses: -(7(z+3)), so:

7(z+3)

We multiply parentheses

7z+21

Back to the equation:

-(7z+21)



We add all the numbers together, and all the variables

6z-(7z+21)+12=0

We get rid of parentheses

6z-7z-21+12=0

We add all the numbers together, and all the variables

-1z-9=0

We move all terms containing z to the left, all other terms to the right

-z=9

z=9/-1

z=-9

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