-5(-3a+2)=4(-a-3)

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Solution for -5(-3a+2)=4(-a-3) equation: 



-5(-3a+2)=4(-a-3)

We move all terms to the left:

-5(-3a+2)-(4(-a-3))=0

We add all the numbers together, and all the variables

-5(-3a+2)-(4(-1a-3))=0

We multiply parentheses

15a-(4(-1a-3))-10=0



We calculate terms in parentheses: -(4(-1a-3)), so:

4(-1a-3)

We multiply parentheses

-4a-12

Back to the equation:

-(-4a-12)



We get rid of parentheses

15a+4a+12-10=0

We add all the numbers together, and all the variables

19a+2=0

We move all terms containing a to the left, all other terms to the right

19a=-2

a=-2/19

a=-2/19

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